systemd: Put libudev in a separate output

This way, packages that need libudev (like Mesa) don't pull in all of
systemd as a runtime dependency.
This commit is contained in:
Eelco Dolstra 2013-06-26 13:34:55 +02:00
parent 552fd3d599
commit 15bd0f4beb
2 changed files with 23 additions and 2 deletions

View file

@ -14,6 +14,8 @@ stdenv.mkDerivation rec {
sha256 = "07gvn3rpski8sh1nz16npjf2bvj0spsjdwc5px9685g2pi6kxcb1";
};
outputs = [ "out" "man" "libudev" ];
patches =
[ ./0001-Make-systemctl-daemon-reexec-do-the-right-thing-on-N.patch
./0002-Ignore-duplicate-paths-in-systemctl-start.patch
@ -65,6 +67,8 @@ stdenv.mkDerivation rec {
substituteInPlace src/journal/catalog.c \
--replace /usr/lib/systemd/catalog/ $out/lib/systemd/catalog/
export NIX_CFLAGS_LINK+=" -Wl,-rpath,$libudev/lib"
'';
PYTHON_BINARY = "${coreutils}/bin/env python"; # don't want a build time dependency on Python
@ -114,6 +118,20 @@ stdenv.mkDerivation rec {
done
rm -rf $out/etc/rpm
# Move libudev to a separate output.
mkdir -p $libudev/lib/pkgconfig $libudev/include
mv $out/lib/libudev* $libudev/lib/
mv $out/lib/pkgconfig/libudev*.pc $libudev/lib/pkgconfig/
mv $out/include/libudev.h $libudev/include/
for i in $libudev/lib/*.la $libudev/lib/pkgconfig/*.pc; do
substituteInPlace $i --replace $out $libudev
done
# FIXME: move into stdenv
prefix="$libudev" patchELF
prefix="$libudev" stripDirs "lib" "''${stripDebugFlags:--S}"
''; # */
enableParallelBuilding = true;

View file

@ -6637,7 +6637,9 @@ let
sysstat = callPackage ../os-specific/linux/sysstat { };
systemd = callPackage ../os-specific/linux/systemd { };
systemd = callPackage ../os-specific/linux/systemd {
stdenv = stdenvMulti;
};
sysvinit = callPackage ../os-specific/linux/sysvinit { };
@ -6679,7 +6681,8 @@ let
});
udev145 = callPackage ../os-specific/linux/udev/145.nix { };
udev = pkgs.systemd;
udev = pkgs.systemd.libudev;
udisks1 = callPackage ../os-specific/linux/udisks/1-default.nix { };
udisks2 = callPackage ../os-specific/linux/udisks/2-default.nix { };