VMware: Allow users to specify DVS switch version (#32925)
This fix adds option to specify DVS Switch version which is tuneable parameter.
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1 changed files with 11 additions and 1 deletions
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@ -22,7 +22,7 @@ description:
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version_added: 2.0
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author: "Joseph Callen (@jcpowermac)"
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notes:
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- Tested on vSphere 5.5
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- Tested on vSphere 6.5
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requirements:
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- "python >= 2.6"
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- PyVmomi
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@ -35,6 +35,12 @@ options:
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description:
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- The name of the switch to create or remove
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required: True
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switch_version:
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description:
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- The version of the switch to create. Can be 6.5.0, 6.0.0, 5.5.0, 5.1.0, 5.0.0 with a vcenter running vSphere 6.5
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- Needed if you have a vcenter version > ESXi version to join DVS. If not specified version=version of vcenter
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required: False
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version_added: 2.5
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mtu:
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description:
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- The switch maximum transmission unit
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@ -77,6 +83,7 @@ EXAMPLES = '''
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password: vcenter_password
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datacenter_name: datacenter
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switch_name: dvSwitch
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switch_version: 6.0.0
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mtu: 9000
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uplink_quantity: 2
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discovery_proto: lldp
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@ -106,6 +113,7 @@ class VMwareDVSwitch(object):
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self.module = module
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self.dvs = None
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self.switch_name = self.module.params['switch_name']
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self.switch_version = self.module.params['switch_version']
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self.datacenter_name = self.module.params['datacenter_name']
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self.mtu = self.module.params['mtu']
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self.uplink_quantity = self.module.params['uplink_quantity']
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@ -151,6 +159,7 @@ class VMwareDVSwitch(object):
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spec.productInfo = vim.dvs.ProductSpec()
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spec.productInfo.name = "DVS"
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spec.productInfo.vendor = "VMware"
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spec.productInfo.version = self.switch_version
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for count in range(1, self.uplink_quantity + 1):
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spec.configSpec.uplinkPortPolicy.uplinkPortName.append("uplink%d" % count)
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@ -193,6 +202,7 @@ def main():
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argument_spec.update(dict(datacenter_name=dict(required=True, type='str'),
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switch_name=dict(required=True, type='str'),
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mtu=dict(required=True, type='int'),
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switch_version=dict(type='str'),
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uplink_quantity=dict(required=True, type='int'),
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discovery_proto=dict(required=True, choices=['cdp', 'lldp'], type='str'),
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discovery_operation=dict(required=True, choices=['both', 'none', 'advertise', 'listen'], type='str'),
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