TypeScript/tests/cases/conformance/types/thisType/inferThisType.ts

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declare function f<T>(g: (this: T) => void): T
declare function h(this: number): void;
f(h)
// works with infer types as well
type Check<T> = T extends (this: infer U, ...args: any[]) => any ? string : unknown;
type r1 = Check<(this: number) => void>; // should be string
type This<T> = T extends (this: infer U, ...args: any[]) => any ? U : unknown;
type r2 = This<(this: number) => void>; // should be number