3 lines
76 B
TypeScript
3 lines
76 B
TypeScript
let ijs: [number, number][] = [[1, 2]];
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ijs = ijs.concat([[3, 4], [5, 6]]);
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let ijs: [number, number][] = [[1, 2]];
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ijs = ijs.concat([[3, 4], [5, 6]]);
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