TypeScript/tests/cases/compiler/relationalOperatorComparable.ts
Nathan Shively-Sanders e301cfe58c Raise literal type to its base in a comparison
Similar to ===, except that it always applies, even when comparing two
literals.
2016-11-10 14:29:48 -08:00

16 lines
611 B
TypeScript

function f(onethree: 1 | 3, two: 2) {
const t = true;
const f = false;
let a1 = onethree < two; // ok
let a2 = onethree < true; // error, number and boolean
let a3 = onethree <= false; // error, number and boolean
let a4 = onethree >= t; // error, number and boolean
let a5 = onethree > f; // error, number and boolean
let a6 = true < onethree; // error, boolean and number
let a7 = false < two; // error, boolean and number
let a8 = 'foo' < onethree; // error, string and number
let a9 = onethree < 1; // ok
let a10 = 1 < two; // ok
let a11 = 2 < 1; // ok
}