TypeScript/tests/cases/conformance/expressions/superPropertyAccess/superPropertyAccessNoError.ts
2016-05-24 13:07:34 -07:00

70 lines
1.5 KiB
TypeScript

// @target: es5
//super.publicInstanceMemberFunction in constructor of derived class
//super.publicInstanceMemberFunction in instance member function of derived class
//super.publicInstanceMemberFunction in instance member accessor(get and set) of derived class
//super.publicInstanceMemberFunction in lambda in member function
//super.publicStaticMemberFunction in static member function of derived class
//super.publicStaticMemberFunction in static member accessor(get and set) of derived class
class SomeBaseClass {
public func() {
return '';
}
static func() {
return 3;
}
returnThis() {
return this;
}
}
class SomeDerivedClass extends SomeBaseClass {
constructor() {
super();
var x = super.func();
var x: string;
}
fn() {
var x = super.func();
var x: string;
var y = () => super.func();
}
get a() {
var x = super.func();
var x: string;
return null;
}
set a(n) {
var x = super.func();
var x: string;
}
static fn() {
var x = super.func();
var x: number;
}
static get a() {
var x = super.func();
var x: number;
return null;
}
static set a(n) {
var x = super.func();
var x: number;
}
returnThis() {
return super.returnThis();
}
}
let instance = new SomeDerivedClass();
instance.returnThis().fn();