9d42ab983d
* implementations: Use declaration name for the span * Always get name in nodeEntry
48 lines
No EOL
1.2 KiB
TypeScript
48 lines
No EOL
1.2 KiB
TypeScript
/// <reference path='fourslash.ts'/>
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// Should not return references to parent interfaces even if the method is declared there
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//// interface SuperFoo {
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//// hello (): void;
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//// }
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////
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//// interface Foo extends SuperFoo {
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//// someOtherFunction(): void;
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//// }
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////
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//// class Bar implements Foo {
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//// [|hello|]() {}
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//// someOtherFunction() {}
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//// }
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////
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//// function createFoo(): Foo {
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//// return {
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//// [|hello|]() {},
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//// someOtherFunction() {}
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//// };
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//// }
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////
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//// var y: Foo = {
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//// [|hello|]() {},
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//// someOtherFunction() {}
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//// };
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////
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//// class FooLike implements SuperFoo {
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//// hello() {}
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//// someOtherFunction() {}
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//// }
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////
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//// class NotRelatedToFoo {
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//// hello() {} // This case is equivalent to the last case, but is not returned because it does not share a common ancestor with Foo
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//// someOtherFunction() {}
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//// }
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////
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//// class NotFoo implements SuperFoo {
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//// hello() {} // We only want implementations of Foo, even though the function is declared in SuperFoo
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//// }
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////
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//// function (x: Foo) {
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//// x.he/*function_call*/llo()
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//// }
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verify.allRangesAppearInImplementationList("function_call"); |