TypeScript/tests/baselines/reference/subtypingWithObjectMembersOptionality.js

89 lines
2 KiB
TypeScript

//// [subtypingWithObjectMembersOptionality.ts]
// Derived member is not optional but base member is, should be ok
interface Base { foo: string; }
interface Derived extends Base { bar: string; }
interface Derived2 extends Derived { baz: string; }
// S is a subtype of a type T, and T is a supertype of S, if one of the following is true, where S' denotes the apparent type (section 3.8.1) of S:
// - S' and T are object types and, for each member M in T, one of the following is true:
// - M is a property and S' contains a property N where
// M and N have the same name,
// the type of N is a subtype of that of M,
// M and N are both public or both private, and
// if M is a required property, N is also a required property.
// - M is an optional property and S' contains no property of the same name as M.
interface T {
Foo?: Base;
}
interface S extends T {
Foo: Derived
}
interface T2 {
1?: Base;
}
interface S2 extends T2 {
1: Derived;
}
interface T3 {
'1'?: Base;
}
interface S3 extends T3 {
'1.': Derived;
}
// object literal case
var a: { Foo?: Base; };
var b = { Foo: <Derived>null };
var r = true ? a : b;
module TwoLevels {
interface T {
Foo?: Base;
}
interface S extends T {
Foo: Derived2
}
interface T2 {
1?: Base;
}
interface S2 extends T2 {
1: Derived2;
}
interface T3 {
'1'?: Base;
}
interface S3 extends T3 {
'1.': Derived2;
}
// object literal case
var a: { Foo?: Base; };
var b = { Foo: <Derived2>null };
var r = true ? a : b;
}
//// [subtypingWithObjectMembersOptionality.js]
// Derived member is not optional but base member is, should be ok
// object literal case
var a;
var b = { Foo: null };
var r = true ? a : b;
var TwoLevels;
(function (TwoLevels) {
// object literal case
var a;
var b = { Foo: null };
var r = true ? a : b;
})(TwoLevels || (TwoLevels = {}));