TypeScript/tests/cases/compiler/strictFunctionTypes1.ts
Anders Hejlsberg 886a6d7473 Fix test
2018-08-20 16:23:09 -07:00

53 lines
1.6 KiB
TypeScript

// @strict: true
// @declaration: true
declare function f1<T>(f1: (x: T) => void, f2: (x: T) => void): (x: T) => void;
declare function f2<T>(obj: T, f1: (x: T) => void, f2: (x: T) => void): T;
declare function f3<T>(obj: T, f1: (x: T) => void, f2: (f: (x: T) => void) => void): T;
interface Func<T> { (x: T): void }
declare function f4<T>(f1: Func<T>, f2: Func<T>): Func<T>;
declare function fo(x: Object): void;
declare function fs(x: string): void;
declare function fx(f: (x: "def") => void): void;
const x1 = f1(fo, fs); // (x: string) => void
const x2 = f2("abc", fo, fs); // "abc"
const x3 = f3("abc", fo, fx); // "abc" | "def"
const x4 = f4(fo, fs); // Func<string>
declare const never: never;
const x10 = f2(never, fo, fs); // string
const x11 = f3(never, fo, fx); // "def"
// Repro from #21112
declare function foo<T>(a: ReadonlyArray<T>): T;
let x = foo([]); // never
// Modified repros from #26127
interface A { a: string }
interface B extends A { b: string }
declare function acceptUnion(x: A | number): void;
declare function acceptA(x: A): void;
declare let a: A;
declare let b: B;
declare function coAndContra<T>(value: T, func: (t: T) => void): T;
const t1: A = coAndContra(a, acceptUnion);
const t2: B = coAndContra(b, acceptA);
const t3: A = coAndContra(never, acceptA);
declare function coAndContraArray<T>(value: T[], func: (t: T) => void): T[];
const t4: A[] = coAndContraArray([a], acceptUnion);
const t5: B[] = coAndContraArray([b], acceptA);
const t6: A[] = coAndContraArray([], acceptA);