9c6af6d841
* Reduce DEFAULT_FALLBACK_FEE to 1,000,000 Koinu. Note this by itself has no effect as the required fee is higher. * Reduce wallet minimum fees to 0.01 DOGE * Update DEFAULT_DUST_LIMIT * Revise derived values after updating recommended fees * Remove fee rounding from RPC tests * Revert tests back to Bitcoin originals where possible
161 lines
7.6 KiB
Python
Executable file
161 lines
7.6 KiB
Python
Executable file
#!/usr/bin/env python3
|
|
# Copyright (c) 2014-2016 The Bitcoin Core developers
|
|
# Distributed under the MIT software license, see the accompanying
|
|
# file COPYING or http://www.opensource.org/licenses/mit-license.php.
|
|
|
|
|
|
from test_framework.test_framework import BitcoinTestFramework
|
|
from test_framework.util import *
|
|
import urllib.parse
|
|
|
|
class AbandonConflictTest(BitcoinTestFramework):
|
|
def __init__(self):
|
|
super().__init__()
|
|
self.num_nodes = 2
|
|
self.setup_clean_chain = False
|
|
|
|
def setup_network(self):
|
|
self.nodes = []
|
|
self.nodes.append(start_node(0, self.options.tmpdir, ["-debug","-logtimemicros","-minrelaytxfee=0.00001"]))
|
|
self.nodes.append(start_node(1, self.options.tmpdir, ["-debug","-logtimemicros"]))
|
|
connect_nodes(self.nodes[0], 1)
|
|
|
|
def run_test(self):
|
|
self.nodes[1].generate(100)
|
|
sync_blocks(self.nodes)
|
|
balance = self.nodes[0].getbalance()
|
|
txA = self.nodes[0].sendtoaddress(self.nodes[0].getnewaddress(), Decimal("10"))
|
|
txB = self.nodes[0].sendtoaddress(self.nodes[0].getnewaddress(), Decimal("10"))
|
|
txC = self.nodes[0].sendtoaddress(self.nodes[0].getnewaddress(), Decimal("10"))
|
|
sync_mempools(self.nodes)
|
|
self.nodes[1].generate(1)
|
|
|
|
sync_blocks(self.nodes)
|
|
newbalance = self.nodes[0].getbalance()
|
|
assert(balance - newbalance < Decimal("0.01")) #no more than fees lost
|
|
balance = newbalance
|
|
|
|
url = urllib.parse.urlparse(self.nodes[1].url)
|
|
self.nodes[0].disconnectnode(url.hostname+":"+str(p2p_port(1)))
|
|
|
|
# Identify the 10btc outputs
|
|
nA = next(i for i, vout in enumerate(self.nodes[0].getrawtransaction(txA, 1)["vout"]) if vout["value"] == Decimal("10"))
|
|
nB = next(i for i, vout in enumerate(self.nodes[0].getrawtransaction(txB, 1)["vout"]) if vout["value"] == Decimal("10"))
|
|
nC = next(i for i, vout in enumerate(self.nodes[0].getrawtransaction(txC, 1)["vout"]) if vout["value"] == Decimal("10"))
|
|
|
|
inputs =[]
|
|
# spend 10btc outputs from txA and txB
|
|
inputs.append({"txid":txA, "vout":nA})
|
|
inputs.append({"txid":txB, "vout":nB})
|
|
outputs = {}
|
|
|
|
outputs[self.nodes[0].getnewaddress()] = Decimal("14.99998")
|
|
outputs[self.nodes[1].getnewaddress()] = Decimal("5")
|
|
signed = self.nodes[0].signrawtransaction(self.nodes[0].createrawtransaction(inputs, outputs))
|
|
txAB1 = self.nodes[0].sendrawtransaction(signed["hex"])
|
|
|
|
# Identify the 14.99998btc output
|
|
nAB = next(i for i, vout in enumerate(self.nodes[0].getrawtransaction(txAB1, 1)["vout"]) if vout["value"] == Decimal("14.99998"))
|
|
|
|
#Create a child tx spending AB1 and C
|
|
inputs = []
|
|
inputs.append({"txid":txAB1, "vout":nAB})
|
|
inputs.append({"txid":txC, "vout":nC})
|
|
outputs = {}
|
|
outputs[self.nodes[0].getnewaddress()] = Decimal("24.9996")
|
|
signed2 = self.nodes[0].signrawtransaction(self.nodes[0].createrawtransaction(inputs, outputs))
|
|
txABC2 = self.nodes[0].sendrawtransaction(signed2["hex"])
|
|
|
|
# In mempool txs from self should increase balance from change
|
|
newbalance = self.nodes[0].getbalance()
|
|
assert_equal(newbalance, balance - Decimal("30") + Decimal("24.9996"))
|
|
balance = newbalance
|
|
|
|
# Restart the node with a higher min relay fee so the parent tx is no longer in mempool
|
|
# TODO: redo with eviction
|
|
# Note had to make sure tx did not have AllowFree priority
|
|
stop_node(self.nodes[0],0)
|
|
self.nodes[0]=start_node(0, self.options.tmpdir, ["-debug","-logtimemicros","-minrelaytxfee=0.0001"])
|
|
|
|
# Verify txs no longer in mempool
|
|
assert_equal(len(self.nodes[0].getrawmempool()), 0)
|
|
|
|
# Not in mempool txs from self should only reduce balance
|
|
# inputs are still spent, but change not received
|
|
newbalance = self.nodes[0].getbalance()
|
|
assert_equal(newbalance, balance - Decimal("24.9996"))
|
|
# Unconfirmed received funds that are not in mempool, also shouldn't show
|
|
# up in unconfirmed balance
|
|
unconfbalance = self.nodes[0].getunconfirmedbalance() + self.nodes[0].getbalance()
|
|
assert_equal(unconfbalance, newbalance)
|
|
# Also shouldn't show up in listunspent
|
|
assert(not txABC2 in [utxo["txid"] for utxo in self.nodes[0].listunspent(0)])
|
|
balance = newbalance
|
|
|
|
# Abandon original transaction and verify inputs are available again
|
|
# including that the child tx was also abandoned
|
|
self.nodes[0].abandontransaction(txAB1)
|
|
newbalance = self.nodes[0].getbalance()
|
|
assert_equal(newbalance, balance + Decimal("30"))
|
|
balance = newbalance
|
|
|
|
# Verify that even with a low min relay fee, the tx is not reaccepted from wallet on startup once abandoned
|
|
stop_node(self.nodes[0],0)
|
|
self.nodes[0]=start_node(0, self.options.tmpdir, ["-debug","-logtimemicros","-minrelaytxfee=0.00001"])
|
|
assert_equal(len(self.nodes[0].getrawmempool()), 0)
|
|
assert_equal(self.nodes[0].getbalance(), balance)
|
|
|
|
# But if its received again then it is unabandoned
|
|
# And since now in mempool, the change is available
|
|
# But its child tx remains abandoned
|
|
self.nodes[0].sendrawtransaction(signed["hex"])
|
|
newbalance = self.nodes[0].getbalance()
|
|
assert_equal(newbalance, balance - Decimal("20") + Decimal("14.99998"))
|
|
balance = newbalance
|
|
|
|
# Send child tx again so its unabandoned
|
|
self.nodes[0].sendrawtransaction(signed2["hex"])
|
|
newbalance = self.nodes[0].getbalance()
|
|
assert_equal(newbalance, balance - Decimal("10") - Decimal("14.99998") + Decimal("24.9996"))
|
|
balance = newbalance
|
|
|
|
# Remove using high relay fee again
|
|
stop_node(self.nodes[0],0)
|
|
self.nodes[0]=start_node(0, self.options.tmpdir, ["-debug","-logtimemicros","-minrelaytxfee=0.0001"])
|
|
assert_equal(len(self.nodes[0].getrawmempool()), 0)
|
|
newbalance = self.nodes[0].getbalance()
|
|
assert_equal(newbalance, balance - Decimal("24.9996"))
|
|
balance = newbalance
|
|
|
|
# Create a double spend of AB1 by spending again from only A's 10 output
|
|
# Mine double spend from node 1
|
|
inputs =[]
|
|
inputs.append({"txid":txA, "vout":nA})
|
|
outputs = {}
|
|
outputs[self.nodes[1].getnewaddress()] = Decimal("9.999")
|
|
tx = self.nodes[0].createrawtransaction(inputs, outputs)
|
|
signed = self.nodes[0].signrawtransaction(tx)
|
|
self.nodes[1].sendrawtransaction(signed["hex"])
|
|
self.nodes[1].generate(1)
|
|
|
|
connect_nodes(self.nodes[0], 1)
|
|
sync_blocks(self.nodes)
|
|
|
|
# Verify that B and C's 10 BTC outputs are available for spending again because AB1 is now conflicted
|
|
newbalance = self.nodes[0].getbalance()
|
|
assert_equal(newbalance, balance + Decimal("20"))
|
|
balance = newbalance
|
|
|
|
# There is currently a minor bug around this and so this test doesn't work. See Issue #7315
|
|
# Invalidate the block with the double spend and B's 10 BTC output should no longer be available
|
|
# Don't think C's should either
|
|
self.nodes[0].invalidateblock(self.nodes[0].getbestblockhash())
|
|
newbalance = self.nodes[0].getbalance()
|
|
#assert_equal(newbalance, balance - Decimal("10"))
|
|
print("If balance has not declined after invalidateblock then out of mempool wallet tx which is no longer")
|
|
print("conflicted has not resumed causing its inputs to be seen as spent. See Issue #7315")
|
|
print(str(balance) + " -> " + str(newbalance) + " ?")
|
|
|
|
if __name__ == '__main__':
|
|
AbandonConflictTest().main()
|