dogecoin/test/functional/mempool_package_onemore.py
Matt Corallo 5ce822efbe Conservatively accept RBF bumps bumping one tx at the package limits
Accept RBF bumps of single transactions (ie which conflict with one
transaction) even when that transaction is a member of a package
which is currently at the package limit iff the new transaction
does not add any additional mempool dependencies from the original.

This could be made a bit looser in the future and still be safe,
but for now this fixes the case that a transaction which was
accepted by the carve-out rule will not be directly RBF'able.
2019-09-04 15:53:14 -04:00

93 lines
4.9 KiB
Python
Executable file

#!/usr/bin/env python3
# Copyright (c) 2014-2019 The Bitcoin Core developers
# Distributed under the MIT software license, see the accompanying
# file COPYING or http://www.opensource.org/licenses/mit-license.php.
"""Test descendant package tracking carve-out allowing one final transaction in
an otherwise-full package as long as it has only one parent and is <= 10k in
size.
"""
from decimal import Decimal
from test_framework.test_framework import BitcoinTestFramework
from test_framework.util import assert_equal, assert_raises_rpc_error, satoshi_round
MAX_ANCESTORS = 25
MAX_DESCENDANTS = 25
class MempoolPackagesTest(BitcoinTestFramework):
def set_test_params(self):
self.num_nodes = 1
self.extra_args = [["-maxorphantx=1000"]]
def skip_test_if_missing_module(self):
self.skip_if_no_wallet()
# Build a transaction that spends parent_txid:vout
# Return amount sent
def chain_transaction(self, node, parent_txids, vouts, value, fee, num_outputs):
send_value = satoshi_round((value - fee)/num_outputs)
inputs = []
for (txid, vout) in zip(parent_txids, vouts):
inputs.append({'txid' : txid, 'vout' : vout})
outputs = {}
for i in range(num_outputs):
outputs[node.getnewaddress()] = send_value
rawtx = node.createrawtransaction(inputs, outputs, 0, True)
signedtx = node.signrawtransactionwithwallet(rawtx)
txid = node.sendrawtransaction(signedtx['hex'])
fulltx = node.getrawtransaction(txid, 1)
assert len(fulltx['vout']) == num_outputs # make sure we didn't generate a change output
return (txid, send_value)
def run_test(self):
# Mine some blocks and have them mature.
self.nodes[0].generate(101)
utxo = self.nodes[0].listunspent(10)
txid = utxo[0]['txid']
vout = utxo[0]['vout']
value = utxo[0]['amount']
fee = Decimal("0.0002")
# MAX_ANCESTORS transactions off a confirmed tx should be fine
chain = []
for _ in range(4):
(txid, sent_value) = self.chain_transaction(self.nodes[0], [txid], [vout], value, fee, 2)
vout = 0
value = sent_value
chain.append([txid, value])
for _ in range(MAX_ANCESTORS - 4):
(txid, sent_value) = self.chain_transaction(self.nodes[0], [txid], [0], value, fee, 1)
value = sent_value
chain.append([txid, value])
(second_chain, second_chain_value) = self.chain_transaction(self.nodes[0], [utxo[1]['txid']], [utxo[1]['vout']], utxo[1]['amount'], fee, 1)
# Check mempool has MAX_ANCESTORS + 1 transactions in it
assert_equal(len(self.nodes[0].getrawmempool(True)), MAX_ANCESTORS + 1)
# Adding one more transaction on to the chain should fail.
assert_raises_rpc_error(-26, "too-long-mempool-chain, too many unconfirmed ancestors [limit: 25]", self.chain_transaction, self.nodes[0], [txid], [0], value, fee, 1)
# ...even if it chains on from some point in the middle of the chain.
assert_raises_rpc_error(-26, "too-long-mempool-chain, too many descendants", self.chain_transaction, self.nodes[0], [chain[2][0]], [1], chain[2][1], fee, 1)
assert_raises_rpc_error(-26, "too-long-mempool-chain, too many descendants", self.chain_transaction, self.nodes[0], [chain[1][0]], [1], chain[1][1], fee, 1)
# ...even if it chains on to two parent transactions with one in the chain.
assert_raises_rpc_error(-26, "too-long-mempool-chain, too many descendants", self.chain_transaction, self.nodes[0], [chain[0][0], second_chain], [1, 0], chain[0][1] + second_chain_value, fee, 1)
# ...especially if its > 40k weight
assert_raises_rpc_error(-26, "too-long-mempool-chain, too many descendants", self.chain_transaction, self.nodes[0], [chain[0][0]], [1], chain[0][1], fee, 350)
# But not if it chains directly off the first transaction
(replacable_txid, replacable_orig_value) = self.chain_transaction(self.nodes[0], [chain[0][0]], [1], chain[0][1], fee, 1)
# and the second chain should work just fine
self.chain_transaction(self.nodes[0], [second_chain], [0], second_chain_value, fee, 1)
# Make sure we can RBF the chain which used our carve-out rule
second_tx_outputs = {self.nodes[0].getrawtransaction(replacable_txid, True)["vout"][0]['scriptPubKey']['addresses'][0]: replacable_orig_value - (Decimal(1) / Decimal(100))}
second_tx = self.nodes[0].createrawtransaction([{'txid': chain[0][0], 'vout': 1}], second_tx_outputs)
signed_second_tx = self.nodes[0].signrawtransactionwithwallet(second_tx)
self.nodes[0].sendrawtransaction(signed_second_tx['hex'])
# Finally, check that we added two transactions
assert_equal(len(self.nodes[0].getrawmempool(True)), MAX_ANCESTORS + 3)
if __name__ == '__main__':
MempoolPackagesTest().main()