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Merge pull request #88730 from mairaw/typo

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fix typo
This commit is contained in:
Rob Lourens 2020-01-16 10:00:15 -08:00 committed by GitHub
parent 9e1d730cf2 71ed221b0e
commit 8c0a573b9e
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GPG key ID: 4AEE18F83AFDEB23
3 changed files with 4 additions and 4 deletions
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4
extensions/emmet/src/abbreviationActions.ts
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@ -94,8 +94,8 @@ function doWrapping(individualLines: boolean, args: any) {
} else {
const wholeFirstLine = editor.document.lineAt(rangeToReplace.start).text;
const otherMatches = wholeFirstLine.match(/^(\s*)/);
const preceedingWhitespace = otherMatches ? otherMatches[1] : '';
textToWrapInPreview = rangeToReplace.isSingleLine ? [textToReplace] : ['\n\t' + textToReplace.split('\n' + preceedingWhitespace).join('\n\t') + '\n'];
const precedingWhitespace = otherMatches ? otherMatches[1] : '';
textToWrapInPreview = rangeToReplace.isSingleLine ? [textToReplace] : ['\n\t' + textToReplace.split('\n' + precedingWhitespace).join('\n\t') + '\n'];
}
textToWrapInPreview = textToWrapInPreview.map(e => e.replace(/(\$\d)/g, '\\$1'));

2
extensions/typescript-language-features/src/features/completions.ts
View file

@ -594,7 +594,7 @@ class TypeScriptCompletionItemProvider implements vscode.CompletionItemProvider
): boolean {
if (this.client.apiVersion.lt(API.v320)) {
// Workaround for https://github.com/Microsoft/TypeScript/issues/27742
// Only enable dot completions when previous character not a dot preceeded by whitespace.
// Only enable dot completions when previous character not a dot preceded by whitespace.
// Prevents incorrectly completing while typing spread operators.
if (position.character > 1) {
const preText = document.getText(new vscode.Range(

2
src/vs/workbench/services/search/node/ripgrepTextSearchEngine.ts
View file

@ -532,7 +532,7 @@ export type IRgBytesOrText = { bytes: string } | { text: string };
export function fixRegexNewline(pattern: string): string {
// Replace an unescaped $ at the end of the pattern with \r?$
// Match $ preceeded by none or even number of literal \
// Match $ preceded by none or even number of literal \
return pattern.replace(/(?<=[^\\]|^)(\\\\)*\\n/g, '$1\\r?\\n');
}