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Handle fact that _generate_room_entry may not return a room entry

This commit is contained in:
Erik Johnston 2016-09-17 18:01:54 +01:00
parent a298331de4
commit 81570abfb2

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@ -135,20 +135,33 @@ class RoomListHandler(BaseHandler):
rooms_to_scan = rooms_to_scan[:since_token.current_limit]
rooms_to_scan.reverse()
# If there's no search filter just limit the range since we'll
# return the vast majority of things.
if limit and not search_filter:
rooms_to_scan = rooms_to_scan[:limit + 1]
# Actually generate the entries. _generate_room_entry will append to
# chunk but will stop if len(chunk) > limit
chunk = []
if limit and not search_filter:
step = limit + 1
for i in xrange(0 , len(rooms_to_scan), step):
# We iterate here because the vast majority of cases we'll stop
# at first iteration, but occaisonally _generate_room_entry
# won't append to the chunk and so we need to loop again.
# We don't want to scan over the entire range either as that
# would potentially waste a lot of work.
yield concurrently_execute(
lambda r: self._generate_room_entry(
r, rooms_to_num_joined[r],
chunk, limit, search_filter
),
rooms_to_scan, 10
rooms_to_scan[i:i + step], 10
)
if len(chunk) >= limit + 1:
break
else:
yield concurrently_execute(
lambda r: self._generate_room_entry(
r, rooms_to_num_joined[r],
chunk, limit, search_filter
),
rooms_to_scan, 5
)
chunk.sort(key=lambda e: (-e["num_joined_members"], e["room_id"]))